SOLUTION: I'm kind of confused by this: A rectangle is twice as long as it is wide, and it has an area of 20 square meters. None of the factors of twenty fit the description and I've tried

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I'm kind of confused by this: A rectangle is twice as long as it is wide, and it has an area of 20 square meters. None of the factors of twenty fit the description and I've tried      Log On


   



Question 850966: I'm kind of confused by this: A rectangle is twice as long as it is wide, and
it has an area of 20 square meters.
None of the factors of twenty fit the description and I've tried to find the right two numbers (decimals) but I'm really confused.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Let x represent the width
Question states***
2x%2Ax+=+20m%5E2
2x^2-20 = 0
x^2 = 10 (Tossing out the negative solution for unit measure)
x = sqrt(10)
CHECKING our answer***
20 = 20
Wish You the Best in your Studies.