# SOLUTION: Solve. We are working with Quadratic Equations and Functions You have 188 ft of fencing to enclose a rectangular region. What is the maximum area?

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 Question 84576: Solve. We are working with Quadratic Equations and Functions You have 188 ft of fencing to enclose a rectangular region. What is the maximum area? Answer by ankor@dixie-net.com(15746)   (Show Source): You can put this solution on YOUR website!Solve. We are working with Quadratic Equations and Functions: : You have 188 ft of fencing to enclose a rectangular region. What is the maximum area? Perimeter: 2L + 2W = 188 Simplify, divide equation by 2: L + W = 94 W = 94 - L : Let x = length Then: (94-x) = width : The area = y: y = x(94-x) y = -x^2 + 94x; a quadratic equation: : Find the axis of symmetry: x = -b/(2a) In our equation: a = -1; b = +94 x = -94/(2*-1) x = -94/-2 x = +47 the axis of symmetry :' Substitute 47 for x in the equation to find the vertex (max) y = -(47^2) + 94(47) y = -2209 + 4418 y = +2209 sq/ft max area with 188 ft perimeter