SOLUTION: The volume of a box is a^3-7a^2+2a+40. It's length is a+2. It's width is a-4. What is the height? My original answer was a+2, but that is incorrect.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The volume of a box is a^3-7a^2+2a+40. It's length is a+2. It's width is a-4. What is the height? My original answer was a+2, but that is incorrect.       Log On


   



Question 842426: The volume of a box is a^3-7a^2+2a+40. It's length is a+2. It's width is a-4. What is the height? My original answer was a+2, but that is incorrect.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
V=Lwh the meanings being expected.
If you want h, you can find that h=V/(Lw). Since you have only polynomial expressions for the three "given" variables, your variable to solve, h, must still be, ..., variable result.

Try polynomial or synthetic division with one expression as divisor at a time among a+2 and a-4. Before trying, MAYBE both are roots of the cubic volume polynomail? Not know until you try.


Abbreviated Results:
Volume divided by a+2:________a%5E2-9a%2B20 which is w*h
That area divided by a-4:_______a-5 which is h

The height is highlight%28a-5%29