SOLUTION: Given that the quadratic equation x^2-2x-m+1=0 has 2 positive real number roots, α and β, determine the range of values of m.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Given that the quadratic equation x^2-2x-m+1=0 has 2 positive real number roots, α and β, determine the range of values of m.      Log On


   

Question 841879: Given that the quadratic equation x^2-2x-m+1=0 has 2 positive real number roots, α and β, determine the range of values of m.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

x^2-2x -m+1=0  |ax^2 + bx + c = 0, where c = (-m+1)

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%282+%2B-+sqrt%28+4-4%28-m%2B1%29%29%29%2F2+

has 2 positive real number roots ⇒

   0 < 4-4(-m+1)< 4 

  0 < 4 + 4m - 4 < 4

   0 < 4m < 4

    0 < m < 1