SOLUTION: Determine the range of the values of k at which the quadratic equation 3x^2+8x+2k=0 will have 2 different negative real number solutions.

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Question 841877: Determine the range of the values of k at which the quadratic equation 3x^2+8x+2k=0 will have 2 different negative real number solutions.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

3x^2+8x+2k=0  |ax^2 + bx + c = 0, where c = 2k

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-16+%2B-+sqrt%28+64-24k%29%29%29%2F6+

2 different negative real number solutions ⇒

   0 < 64-24k < 256

  -64 < -24k < 192

   64/24 > k > -8

    -8 < k < 8/3