SOLUTION: Factor by grouping. x^3 – 3x^2 + 4x – 12

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Question 83973: Factor by grouping. x^3 – 3x^2 + 4x – 12
Answer by Nate(3500) About Me  (Show Source):
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x^3 – 3x^2 + 4x – 12
(x^3 – 3x^2) + (4x – 12)
x^2(x – 3) + 4(x – 3)
(x^2 + 4)(x – 3)