SOLUTION: I am having trouble with this homeowrk question which states: Solve 2x^2-8x+1=0 by completing the square. So far I have 1/2(2x^2-8x)=1/2(-1)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I am having trouble with this homeowrk question which states: Solve 2x^2-8x+1=0 by completing the square. So far I have 1/2(2x^2-8x)=1/2(-1)       Log On


   

Question 83654: I am having trouble with this homeowrk question which states: Solve 2x^2-8x+1=0 by completing the square. So far I have 1/2(2x^2-8x)=1/2(-1)
x^2-4x=-1/2
What now?!?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
take half of the coefficient of the x term, square it, and add (to both sides) ... then factor, and take square root

x^2-4x+(-2)^2=(-1/2)+(-2)^2 ... x^2-4x+4=7/2 ... (x-2)^2=7/2 ... x-2=sqrt%287%2F2%29 ... x=%282+%2B-+sqrt%287%2F2%29%29