SOLUTION: how would you put 2x^2-12+2x=(x-2)^2+2 in the standard form ax^2+bx+c=0

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Question 825472: how would you put 2x^2-12+2x=(x-2)^2+2 in the standard form ax^2+bx+c=0
Found 2 solutions by unlockmath, josgarithmetic:
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
First we want to expand this 2x^2-12+2x=(x-2)^2+2 as:
2x^2-12+2x= x^2-4x+4+2
Now we can get everything on one side to look like this:
x^2+6x-18=0
Make sense?
RJ
www.math-unlock.com

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Another Complete-the-Square question!

2x%5E2-12%2B2x=x%5E2-4x%2B4%2B2
x%5E2-12%2B2x=-4x%2B6
x%5E2%2B6x-18=0
'
The rectangular area x%5E2%2B6x being x accross x+6, is missing the square piece, %286%2F2%29%5E2=3%5E2=9.
'
x%5E2%2B6x%2B%289-9%29-18=0
x%5E2%2B6x%2B9-9-18=0
highlight%28%28x%2B3%29%5E2-27%29=0, DONE.