SOLUTION: Solve the problem.
The manufacturer of a CD player has found that the revenue R (in dollars) is
R(p)=-5p(squared)+1330p when the unit price is p dollars. If the manufacturer
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Quadratic Equations and Parabolas
-> SOLUTION: Solve the problem.
The manufacturer of a CD player has found that the revenue R (in dollars) is
R(p)=-5p(squared)+1330p when the unit price is p dollars. If the manufacturer
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Question 824418: Solve the problem.
The manufacturer of a CD player has found that the revenue R (in dollars) is
R(p)=-5p(squared)+1330p when the unit price is p dollars. If the manufacturer sets the price p to maximize revenue, what is the maximum revenue to the nearest whole dollar? Found 2 solutions by stanbon, josgarithmetic:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The manufacturer of a CD player has found that the revenue R (in dollars) is
R(p)=-5p(squared)+1330p when the unit price is p dollars. If the manufacturer sets the price p to maximize revenue, what is the maximum revenue to the nearest whole dollar?
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To find maximum R(p)
1. Find the vertex of R(p)
OR
2. Find and solve the derivative of R(p) ; if you know calculus.
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Find the vertex::
Max occurs when p = -b/(2a) = -1330/(2(-5)) = 133
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Max Revenue = R(133) = $88445
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Cheers,
Stan H.
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You can put this solution on YOUR website!
' will have a maximum.
For this maximum,
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Looking at the middle of the two possible p values, is where the maximum revenue should be.
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