SOLUTION: Evaluate A = {{{(a^2 − 3a +1)^2 − (1− a)(−2a +1)(1− 3a)}}} . Then WITHOUT doing any further calculation write down the value of B = {{{(a^2 + 3a +1)^

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Evaluate A = {{{(a^2 − 3a +1)^2 − (1− a)(−2a +1)(1− 3a)}}} . Then WITHOUT doing any further calculation write down the value of B = {{{(a^2 + 3a +1)^      Log On


   

Question 823758: Evaluate A = . Then WITHOUT doing any
further calculation write down the value of B = %28a%5E2+%2B+3a+%2B1%29%5E2+%26%238722%3B+%281%2B+a%29%282a+%2B1%29%281%2B+3a%29 .
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Too much gibberish.