SOLUTION: [ 14x + 6 = -4x^2 ] Will the graph of the equation above intersect the x-axis in zero, one, or two points? (Use the quadratic formula to help you answer this question.)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: [ 14x + 6 = -4x^2 ] Will the graph of the equation above intersect the x-axis in zero, one, or two points? (Use the quadratic formula to help you answer this question.)       Log On


   



Question 821948: [ 14x + 6 = -4x^2 ]
Will the graph of the equation above intersect the x-axis in zero, one, or two points?
(Use the quadratic formula to help you answer this question.)

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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14x + 6 = -4x^2
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put into standard form:
-4x^2 - 14x - 6 = 0
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the above quadratic equation is in standard form, with a=-4, b=-14, and c=-6
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-4 -14 -6
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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answer:
the two real roots (i.e. the two x-intercepts), of the quadratic are:
x = -3
x = -0.5
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