SOLUTION: f(x)=-(x+1)^2+4 vertex- line of symmetry- x intercept- y intercept-

 

Hi,

Note: the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

The standard form is , where  the focus is (h,k + p)

f(x)= -(x+1)^2+4 

vertex-  V(-1,4)

line of symmetry-  

x intercept-   0 = -(x+1)^2 + 4,  x = -1  ± 2,  x is  -3,-1

y intercept-