SOLUTION: -6 2/5 x2 + 7 1/5 x - 3 1/5 = 0 A x = {-2 +- i[SQRT(13)]}/2 Bx = {-6 +- i[SQRT(47)]}/16 Cx = {9 +- i[SQRT(21)]}/-2 Dx = {7 +- i[SQRT(126)]}/-2 E x = {-9 +- i[SQRT(47)]}/

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: -6 2/5 x2 + 7 1/5 x - 3 1/5 = 0 A x = {-2 +- i[SQRT(13)]}/2 Bx = {-6 +- i[SQRT(47)]}/16 Cx = {9 +- i[SQRT(21)]}/-2 Dx = {7 +- i[SQRT(126)]}/-2 E x = {-9 +- i[SQRT(47)]}/      Log On


   

Question 814416: -6 2/5 x2 + 7 1/5 x - 3 1/5 = 0
A x = {-2 +- i[SQRT(13)]}/2
Bx = {-6 +- i[SQRT(47)]}/16
Cx = {9 +- i[SQRT(21)]}/-2
Dx = {7 +- i[SQRT(126)]}/-2
E x = {-9 +- i[SQRT(47)]}/-16
F x = {2 +- i[SQRT(126)]}/-6

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
-6 2/5 x2 + 7 1/5 x - 3 1/5 = 0
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Multiply by 5 to eliminate fractions.
-5 might be better.