SOLUTION: Can someone please check this for me? solve by using the quadratic formula x^2=5x+8 x^2=25+8 =-5+-sqrt33/2

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Question 80825: Can someone please check this for me?
solve by using the quadratic formula
x^2=5x+8
x^2=25+8
=-5+-sqrt33/2
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(48546) About Me  (Show Source):
You can put this solution on YOUR website!
solve by using the quadratic formula
x^2=5x+8
x^2-5x-8=0
x=[5+-sqrt(25-4*-8)]/2
x=[5+-sqrt47]/2
x=(5+sqrt47)/2 or x=[5-sqrt47]/2
=========================
x^2=25+8
x^2-25x-8=0
x=[25+-sqrt(625-4*-8)]/2
x=[25+-sqrt657]'2
x=[25+sqrt657]/2 or x=[25-sqrt657]/2
============
Cheers,
Stan H.

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
x%5E2+=+5x%2B8
First, get your equation into the standard form for quadratic equations: ax%5E2%2Bbx%2Bc+=+0 by subtracting 5x from both sides then subtracting 8 from both sides.
x%5E2-5x-8+=+0 Compare this with the standard form and you can see that, in your equation, a = 1, b = -5, and c = -8. Now apply the quadratic formula:x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a to your equation.
x+=+%28-%28-5%29%2B-sqrt%28%28-5%29%5E2-4%281%29%28-8%29%29%29%2F2%281%29 Simplify this.
x+=+%285%2B-sqrt%2825%2B32%29%29%2F2
x+=+%285%2B-sqrt%2857%29%29%2F2
The solutions are:
x+=+%285%2Bsqrt%2857%29%29%2F2 or x+=+%285-sqrt%2857%29%29%2F2