You can put this solution on YOUR website! find two numbers whose sum is 26,if the sum or their squares is 340.
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let x=one of the numbers
26-x=other number
x^2+(26-x)^2=340
x^2+676-52x+x^2=340
2x^2-52x+336=0
x^2-26x+168=0
(x-12)(x-14)=0
x=12
or
x=14
..
one of the numbers=12
other number=14