SOLUTION: The height of an object dropped from a 205 feet tall building is given by h = -16t squared + 205. When will the object be 36 feet above the ground

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 Question 77870: The height of an object dropped from a 205 feet tall building is given by h = -16t squared + 205. When will the object be 36 feet above the groundAnswer by ankor@dixie-net.com(15667)   (Show Source): You can put this solution on YOUR website!The height of an object dropped from a 205 feet tall building is given by h = -16t squared + 205. When will the object be 36 feet above the ground 0 solutions : Substitute 36 for h: -16t^2 + 205 = 36 : -16t^2 = 36 - 205; Subtract 205 from both sides : 16t^2 = 169; multiplied equation by -1 : sqrt(16t^2) = sqrt(169); find the square root of both sides : 4t = 13 : t = 13/4 : t = 3.25 seconds it will be 36 ft above the ground: : : Check by substituting 3.25 for x, in -16t^2 + 205 -16(3.25^2) + 205 = -16(10.5625) + 205 -169 + 205 = 36