SOLUTION: i need help telling if the equation has one, two, or no real solution {{{x^2-3x+4=0}}}

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Question 776366: i need help telling if the equation has one, two, or no real solution x%5E2-3x%2B4=0
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 -3x +4 = 0
use the determinant from the quadratic formula
b^2 -4ac = (-3)^2 - 4*1*4 = 9 -16 = -7
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a negative determinant implies no real solutions