SOLUTION: Describe the nature of the roots of the equation x^2-4x+4=0, when I worked this problem out I got: a=1,b=-4,c=4 d=b^2-4ac d=(-4)^2-4(1)(4) d=16-16=0 the answer 0 is one real

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Describe the nature of the roots of the equation x^2-4x+4=0, when I worked this problem out I got: a=1,b=-4,c=4 d=b^2-4ac d=(-4)^2-4(1)(4) d=16-16=0 the answer 0 is one real       Log On


   

Question 765304: Describe the nature of the roots of the equation x^2-4x+4=0, when I worked this problem out I got:
a=1,b=-4,c=4
d=b^2-4ac
d=(-4)^2-4(1)(4)
d=16-16=0
the answer 0 is one real root according to the "nature of the roots"
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct.
The "one root" is:
-b/(2a)=-(-4)/(2)= 2