SOLUTION: A quadratic equation has a parable that has the roots x = 3 and x = -5. It passes through the point (1, -12). Determine its equation

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A quadratic equation has a parable that has the roots x = 3 and x = -5. It passes through the point (1, -12). Determine its equation       Log On


   



Question 764034: A quadratic equation has a parable that has the roots x = 3 and x = -5. It passes through the point (1, -12). Determine its equation

Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Really? I have heretofore never encountered a quadratic equation that had a normative principle to teach. Is it anything like the parable of the Prodigal Son or perhaps more like the Good Samaritan?

Now, if what you meant to say was that the graph of a quadratic function is a parabola and the function has zeros at and and that the graph contains the point . Then it is possible to derive the equation that defines the function.

The standard form of a quadratic function is

If the function has a zero at , then the point must be on the graph. Therefore:



Likewise, for



and in the case of the point :




Leading us to the following 3X3 system







which translates to the following augmented matrix, the ordered triple solution of which provides the coefficients for your desired function.



John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A quadratic equation has a parabola that has the roots x = 3 and x = -5.
It passes through the point (1, -12).
Determine it's equation.
:
Using the form ax^2 + bx + c = y, write equation for each pair
x=3; y = 0: 9a + 3b + c = 0
x=-.5; y=0: .25a - .5b + c = 0
x=1; y=-12: a + b + c = -12
:
Subtract the 3rd equation from the 1st equation
9a + 3b + c = 0
a + b + c = -12
-----------------
8a + 2b = 12
simplify, divide by 2
4a + b = 6
:
Subtract the 3rd equation from the 2nd equation
.25a - .5b + c = 0
a + b + c = -12
----------------
-.75a - 1.5b = 12
Simplify, divide both sides by -.75
a + 2b = -16
:
Two 2 unknown equations we can solve with elimination
Multiply the 1st by 2, subtract the 2nd
8a + 2b = 12
a + 2b = -16
-----------------subtraction eliminates b, find a
7a = 28
a = 28/7
a = 4
:
Find b using a + 2b = -16
4 + 2b = -16
2b = -20
b = -10
:
Find c
4 - 10 + c = -12
c = -12 + 6
c = -6
:
Our equation: y = 4x^2 - 10x - 6
:
Graphically
+graph%28+300%2C+200%2C+-5%2C+5%2C+-20%2C+10%2C+4x%5E2-10x-+6%29