SOLUTION: Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
2x^2-3x+1=0
ive got so far the last result x=3_+√3*5
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-> SOLUTION: Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
2x^2-3x+1=0
ive got so far the last result x=3_+√3*5
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Question 763958: Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
2x^2-3x+1=0
ive got so far the last result x=3_+√3*5
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4
and then im stuck and confuse. Found 2 solutions by stanbon, solver91311:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the quadratic formula to solve the following. Leave irrational roots in the simplest radical form.
2x^2-3x+1=0
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x = [3 +- sqrt(9-4*2*1)]/4
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x = [3 +- sqrt(1)]/4
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x = (3+1)/4 or x = (3-1)/4
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x = 1 or x = 1/2
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Cheers,
Stan H.
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