SOLUTION: You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the       Log On


   

Question 756138: You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the dimensions of the card? Round to the nearest tenth if necessary.
Any help is appreciated.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the dimensions of the card? Round to the nearest tenth if necessary.
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Width = x
length 2x+1
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Equation:
x(2x+1) = 88
2x^2 + x - 88 = 0
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x = [-1 +- sqrt(1-4*2*-88)}/4
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x = [-1 +- sqrt(1+704)]/4
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x = [-1 +- 26.55]/4
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Positive solution:
x = 25.55/5
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x = 5.11 inches
x+1 = 6.11 inches
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Cheers,
Stan H.
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