SOLUTION: Find the -xintercept(s) and the coordinates of the vertex for the parabola x^2 - 2x - 24=y . If there is more than one -intercept, separate them with commas.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the -xintercept(s) and the coordinates of the vertex for the parabola x^2 - 2x - 24=y . If there is more than one -intercept, separate them with commas.      Log On


   

Question 752526: Find the -xintercept(s) and the coordinates of the vertex for the parabola x^2 - 2x - 24=y . If there is more than one -intercept, separate them with commas.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

+x%5E2+-+2x+-+24=y+
vertex form:
+x%5E2+-+2x+-24=y.....complete square on left side


+%28x%5E2+-2x%2B__%29-24+=y+
+%28x%5E2+-2x%2B1%29+-1-24=y+%2B24
+%28x+-1%29%5E2-25+=y+
vertex: h=1 and k=-25
x-intercepts: set y=0 and solve for x
+%28x+-1%29%5E2-25+=0+
+%28x+-1%29%5E2+=25+
+sqrt%28%28x+-1%29%5E2%29+=sqrt%2825%29+
+x+-1+=5+ or +x+-1+=-5+
if +x+-1+=5+ => +x+=6+
if +x+-1+=-5+ => +x+=-4+

so, x-intercepts are at (6,0) and (-4,0)