SOLUTION: how do i graph this:x to the 2nd power+2=3x

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Question 75032This question is from textbook alegbra 1
: how do i graph this:x to the 2nd power+2=3xThis question is from textbook alegbra 1

Answer by stanbon(48546) About Me  (Show Source):
You can put this solution on YOUR website!
how do i graph this:x to the 2nd power+2=3x
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Rewrite as:
y=x^2-3x+2
You could then plot some points,
or if you know the vertex is at x=-b/2a you would get
x=3/2, then y= (3/2)^2-3(3/2)+2 = (9/4)-18/4+8/4 = -1/4
So the vertex is at (3/2,-1/4)
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The function factors as (x-1)(x-2) so you
have x-intercepts at x=1 and x=2.
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With that information you should be able to graph the parabola which
opens upward.
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-3x%2B2%29
Cheers,
Stan H.