SOLUTION: Find the vertex and intercept only.
y=3-5x+2x^2
I would assume to put them in order, but I'm not really sure from there. Help is Appreciated thanks! :)
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Find the vertex and intercept only.
y=3-5x+2x^2
I would assume to put them in order, but I'm not really sure from there. Help is Appreciated thanks! :)
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Question 749976: Find the vertex and intercept only.
y=3-5x+2x^2
I would assume to put them in order, but I'm not really sure from there. Help is Appreciated thanks! :) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the vertex and intercept only.
y=3-5x+2x^2
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y = 2x^2 - 5x + 3
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2x^2-5x = y-3
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2(x^2-(5/2) + (5/4)^2) = y - 3 + 2(5/4)^2
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2(x+(5/4))^2 = y + 9/64
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Vertex: (-5/4, -9/64)
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y-intercept:
Let x = 0, then y = 3
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Cheers,
Stan H.
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