SOLUTION: Solve {{{(t+5)^2=12}}}

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Question 744535: Solve
%28t%2B5%29%5E2=12
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(t+5)^2=12
t^2+10t+25=12

t^2+10t+13=0
Use the quadratic formula
a= 1 , b= 10 , c= 13

b^2-4ac= 100 + -52
b^2-4ac= 48
%09sqrt%28%0948%09%29=%096.93%09
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=( -10 + 6.93 )/ 2
x1= -1.54
x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x2=( -10 -6.93 ) / 2
x2= -8.46

(-1.536 , -8.46 )

m.ananth@hotmail.ca