SOLUTION: Can you help me solve: A 5 in. photograph is surrounded by a frame of uniform width. The area of the frame equals the area of the photograph. Find the width of the frame.

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Question 72910This question is from textbook Algebra and Trigonometry Structure and Method
: Can you help me solve: A 5 in. photograph is surrounded by a frame of uniform width. The area of the frame equals the area of the photograph. Find the width of the frame. This question is from textbook Algebra and Trigonometry Structure and Method

Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website!
5*5=25 FOR THE AREA OF THEPHOTO.
THE FRAME IS (5+2X)^2 X BEING THE FRAME WIDTH
THUS THE TOTAL AREA IS (5+2X)^2=50 OR
25+20X+4X^2=50
4X^2+20X+25-50=0
4X^2+20X-25=0 USING THE QUADRATIC EQUATION WE GET
X=(-20+-SQRT[20^2-4*4*-25])/2*4
X=(-20+-SQRT[400+400]/8
X=(-20+-sqrt800)/8
X=(-20+-28.28)/8
X=(-20+28.28)/8
X=8.28/8
X=1.0355 IN. ANSWER. THE WIDTH OF THE FRAME.