SOLUTION: really need help on this, can normally solve these.-
the question asks me to plot the following quadratic-
x^2 - x - 6 (x squared minus x minus 6).
my work just dosent seem r
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: really need help on this, can normally solve these.-
the question asks me to plot the following quadratic-
x^2 - x - 6 (x squared minus x minus 6).
my work just dosent seem r
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Question 728790: really need help on this, can normally solve these.-
the question asks me to plot the following quadratic-
x^2 - x - 6 (x squared minus x minus 6).
my work just dosent seem right. iam coming across all these fractions, we never went over this in class. NEED HELP ASAP. Answer by solver91311(24713) (Show Source):
For any quadratic of the form , the graph is a parabola with a vertical line axis of symmetry opening upward if or downward if .
The -coordinate of the vertex is given by . The -coordinate of the vertex is
The axis of symmetry is the line with the equation
The -intercept is the point
Symmetry demands that there is a point on the graph at
The -intercepts, if they exist (and they do exist for your problem) are at and where and are the zeros of the polynomial. In other words, and . Note that your trinomial factors neatly over the integers: -3 + 2 = -1 and -3 X 2 = -6.
Plot the above five points and draw a smooth curve.
For future reference, any quadratic with a non-zero value for the constant term and the constant and lead coefficient have opposite signs, you are guaranteed two distinct real number zeros.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
