SOLUTION: How do you put y= -8x^2+ 3 into vertex form?

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Question 719217: How do you put y= -8x^2+ 3 into vertex form?
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
put y= -8x^2+ 3 into vertex form?
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y = -8(x^2) + 3
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y = -8(x-0)^2 + 3
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vertex: (0,3)
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Cheers,
Stan H.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you put y= -8x^2+ 3 into vertex form?
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Vertex form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex, A is a multiplier which affects the slope or steepness of the curve.
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Given equation is already in vertex form with:
vertex at (0,3) and A=-8