SOLUTION: 2x2 – 5x + 7 = 0 (1 point) 31; one, real 31; two, real –31; one, imaginary –31; two, imaginary 6. –3x2 + 14x – 8 = 0 (1 point) 100; one, real 100; two, real 196; one,

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 2x2 – 5x + 7 = 0 (1 point) 31; one, real 31; two, real –31; one, imaginary –31; two, imaginary 6. –3x2 + 14x – 8 = 0 (1 point) 100; one, real 100; two, real 196; one,       Log On


   



Question 695571: 2x2 – 5x + 7 = 0 (1 point)
31; one, real
31; two, real
–31; one, imaginary
–31; two, imaginary
6. –3x2 + 14x – 8 = 0 (1 point)
100; one, real
100; two, real
196; one, real
196; two, real
7. 4x2 – 5x + 10 = 7x + 1 (1 point)
0; one, real
0; no real solutions
–135, one, imaginary
–135; two, imaginary

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2x2 – 5x + 7 = 0 (1 point)
31; one, real
31; two, real
–31; one, imaginary
–31; two, imaginary
6. –3x2 + 14x – 8 = 0 (1 point)
100; one, real
100; two, real
196; one, real
196; two, real
7. 4x2 – 5x + 10 = 7x + 1 (1 point)
0; one, real
0; no real solutions
–135, one, imaginary
–135; two, imaginary
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