SOLUTION: could you please help me with this question? how long does it take a ball to reach maximum height with the formula {{{h=-16t^2+64t+30}}} where h= height and t=seconds
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-> SOLUTION: could you please help me with this question? how long does it take a ball to reach maximum height with the formula {{{h=-16t^2+64t+30}}} where h= height and t=seconds
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Question 691053: could you please help me with this question? how long does it take a ball to reach maximum height with the formula where h= height and t=seconds Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! how long does it take a ball to reach maximum height with the formula h=-16t^2+24t+30 where h= height and t=seconds
:
The max height occurs at the axis of symmetry which we can find with the formula x = -b/(2a)
In this equatio
t =
t =
t = +.75 seconds to reach max height
:
To find max height, replace t with .75
h = -16(.75^2) + 24(.75) + 30
h = -16(.5625) + 18 + 30
h = -9 + 18 + 30
h = 39 ft is max height occurring .75 seconds after launch
:
Here is a graph of that equation, showing this very clearly
