SOLUTION: can you please help me with this? 25c^2 + 5c - 42 Thanks.

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Question 678301: can you please help me with this?
25c^2 + 5c - 42

Thanks.

Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 25c%5E2%2B5c-42, we can see that the first coefficient is 25, the second coefficient is 5, and the last term is -42.


Now multiply the first coefficient 25 by the last term -42 to get %2825%29%28-42%29=-1050.


Now the question is: what two whole numbers multiply to -1050 (the previous product) and add to the second coefficient 5?


To find these two numbers, we need to list all of the factors of -1050 (the previous product).


Factors of -1050:
1,2,3,5,6,7,10,14,15,21,25,30,35,42,50,70,75,105,150,175,210,350,525,1050
-1,-2,-3,-5,-6,-7,-10,-14,-15,-21,-25,-30,-35,-42,-50,-70,-75,-105,-150,-175,-210,-350,-525,-1050


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -1050.
1*(-1050) = -1050
2*(-525) = -1050
3*(-350) = -1050
5*(-210) = -1050
6*(-175) = -1050
7*(-150) = -1050
10*(-105) = -1050
14*(-75) = -1050
15*(-70) = -1050
21*(-50) = -1050
25*(-42) = -1050
30*(-35) = -1050
(-1)*(1050) = -1050
(-2)*(525) = -1050
(-3)*(350) = -1050
(-5)*(210) = -1050
(-6)*(175) = -1050
(-7)*(150) = -1050
(-10)*(105) = -1050
(-14)*(75) = -1050
(-15)*(70) = -1050
(-21)*(50) = -1050
(-25)*(42) = -1050
(-30)*(35) = -1050

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 5:


First NumberSecond NumberSum
1-10501+(-1050)=-1049
2-5252+(-525)=-523
3-3503+(-350)=-347
5-2105+(-210)=-205
6-1756+(-175)=-169
7-1507+(-150)=-143
10-10510+(-105)=-95
14-7514+(-75)=-61
15-7015+(-70)=-55
21-5021+(-50)=-29
25-4225+(-42)=-17
30-3530+(-35)=-5
-11050-1+1050=1049
-2525-2+525=523
-3350-3+350=347
-5210-5+210=205
-6175-6+175=169
-7150-7+150=143
-10105-10+105=95
-1475-14+75=61
-1570-15+70=55
-2150-21+50=29
-2542-25+42=17
-3035-30+35=5



From the table, we can see that the two numbers -30 and 35 add to 5 (the middle coefficient).


So the two numbers -30 and 35 both multiply to -1050 and add to 5


Now replace the middle term 5c with -30c%2B35c. Remember, -30 and 35 add to 5. So this shows us that -30c%2B35c=5c.


25c%5E2%2Bhighlight%28-30c%2B35c%29-42 Replace the second term 5c with -30c%2B35c.


%2825c%5E2-30c%29%2B%2835c-42%29 Group the terms into two pairs.


5c%285c-6%29%2B%2835c-42%29 Factor out the GCF 5c from the first group.


5c%285c-6%29%2B7%285c-6%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%285c%2B7%29%285c-6%29 Combine like terms. Or factor out the common term 5c-6


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Answer:


So 25c%5E2%2B5c-42 factors to %285c%2B7%29%285c-6%29.


In other words, 25c%5E2%2B5c-42=%285c%2B7%29%285c-6%29.


Note: you can check the answer by expanding %285c%2B7%29%285c-6%29 to get 25c%5E2%2B5c-42 or by graphing the original expression and the answer (the two graphs should be identical).

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

25c%5E2+%2B+5c+-42......replace 5c with -30c%2B35c
25c%5E2+-30c%2B35c+-42.........group

%2825c%5E2+-30c%29%2B%2835c+-42%29

5c%285c+-6%29%2B7%285c+-6%29

%285c%2B7%29%285c+-6%29....now you can set expression equal to zero an find solutions for c

%285c%2B7%29%285c+-6%29=0
if 5c%2B7=0.....=>....5c=-7...=>....c=-7%2F5
or
if 5c+-6=0.....=>....5c=6...=>....c=6%2F5