Question 669514: Given that the quadratic equation
(1-k)x^2+8x+1-k=0
has equal roots, find the possible values of k.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Given that the quadratic equation
(1-k)x^2+8x+1-k=0
has equal roots, find the possible values of k.
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If roots are equal, b^2-4ac = 0
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a = 1-k
b = 8
c = 1-k
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b^2-4ac = 64 - 4(1-k)^2 = 64-4(1-2k+k^2) = -4k^2+8k+60
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Solve:
-4k^2+8k+60 = 0
k^2 -2k - 15 = 0
(k-5)(k+3) = 0
Possible value of "k":
k = 5 or k = -3
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Cheers,
Stan H.
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