SOLUTION: If a football is kicked straight up with an initial velocity of 64 ft/sec from a height of 5 ft, then its height above the earth is a function of time given by h(t)=-16t^2+64t+5.
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-> SOLUTION: If a football is kicked straight up with an initial velocity of 64 ft/sec from a height of 5 ft, then its height above the earth is a function of time given by h(t)=-16t^2+64t+5.
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Question 655988: If a football is kicked straight up with an initial velocity of 64 ft/sec from a height of 5 ft, then its height above the earth is a function of time given by h(t)=-16t^2+64t+5.
What is the maximum height reached by the ball in ft? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! If a football is kicked straight up with an initial velocity of 64 ft/sec from a height of 5 ft, then its height above the earth is a function of time given by h(t)=-16t^2+64t+5.
What is the maximum height reached by the ball in ft?
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It's the vertex of the parabola h(t)=-16t^2+64t+5.
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The time to max height is t = -b/2a = -64/(-32) = 2 seconds
h(2) = -16*4 + 64*2 + 5
= 69 feet
