SOLUTION: in a graph of y=x^2+2x-9 - how would one find the vertex of this graph. Your help would be sincerely appreciated.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: in a graph of y=x^2+2x-9 - how would one find the vertex of this graph. Your help would be sincerely appreciated.      Log On


   

Question 64772: in a graph of y=x^2+2x-9 - how would one find the vertex of this graph. Your help would be sincerely appreciated.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2+2x-9 - how would one find the vertex
--------------
The minimum or maximum occurs when x=-b/2a
In your case x=-2/2=-1
The corresponding y value is:
f(-1)=(-1)^2+2(-1)-9
f(-1)=1-2-9=-10
The vertex is at (-1,-10)
graph%28600%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2%2B2x-9%29
Cheers,
Stan H.