SOLUTION: A box with no top is to be constructed from a piece of cardboard whose length measures 12 inches more than its width. The box is formed by cutting squares that measure 4 inch on ea

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A box with no top is to be constructed from a piece of cardboard whose length measures 12 inches more than its width. The box is formed by cutting squares that measure 4 inch on ea      Log On


   



Question 644775: A box with no top is to be constructed from a piece of cardboard whose length measures 12 inches more than its width. The box is formed by cutting squares that measure 4 inch on each side from the four corners and then folding up the sides.
If the volume of the box 256 in cm^3 what are the dimensions of the piece of cardboard?
The Height?
The width?
It would be appreciated if you can show your work. Thank you! :)

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the width of the piece of cardboard = +w+ in
The length = +w+%2B+12+ in
After the 4 in squares are cut from each corner,
The width = +w+-+8+ in
The length = +w+%2B+12+-+8+ in
Folding the sides up makes the height +4+ in
--------------
The volume is length x width x height, so
+256+=+%28+w+-+8+%29%2A%28+w+%2B+4+%29%2A4+ in3
+256+=+%28+w%5E2+-+8w+%2B+4w+-+32+%29%2A4+
+64+=+w%5E2+-+4w+-+32++
+w%5E2+-+4w+=+96+
Complete the square
+w%5E2+-+4w+%2B+%284%2F2%29%5E2+=+96+%2B+%284%2F2%29%5E2+
+w%5E2+-+4w+%2B+4+=+100+
+%28+w+-+2+%29%5E2+=+10%5E2+
+w+-+2+=+10+
+w+=+12+ in
and length = +12+%2B+12+=+24+ in
The cardboard is 12" x 24"
Height is 4"
Width is 12"
-----------
check:
The volume is
+V+=+%28+w+-+8+%29%2A%28+w+%2B+4+%29%2A4+
+V+=+%28+12+-+8+%29%2A%28+12+%2B+4+%29%2A4+
+V+=+4%2A16%2A4+
+V+=+16%2A16+
+V+=+256+ in3
OK