SOLUTION: I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:
bx^2 + 2x
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-> SOLUTION: I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:
bx^2 + 2x
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Question 638847: I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:
bx^2 + 2x + 1/b = 0 (b does not equal 0) solve for x. Answer by MathTherapy(10551) (Show Source):
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I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:
bx^2 + 2x + 1/b = 0 (b does not equal 0) solve for x.
----- Multiplying by LCD, b
Looking for factors of + 1 (c * a) that sum to + 2 (b). These factors are 1 and 1. The replacement for "b" is therefore, 1bx and 1bx. We now have:
bx(bx + 1) + 1(bx + 1)
(bx + 1)(bx + 1) = 0, or
bx + 1 = 0
bx = - 1
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