SOLUTION: 27x�0…5+ 3x - 10 = 0 solve the following quadratic equation by factoring

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27x^2+3x-10=0 To solve this, we make use of formular x=(-3+-sqrt(3^2-4*27*-10))/2*27 x=-3+-sqrt(9+1080)/54 x=-3+-sqrt(1089)/54 x=-3+-33/54 x=-3+33/54 or -3-33/54 x=30/54 or -36/54 x=5/9 or -2/3

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27x�0…5+ 3x - 10 = 0 solve the following quadratic equation by factoring



Factors of 270 (c * a) whose sum is 3 are: 18 & 15, so replacement for b is: (18x - 15x)

now becomes:

9x(3x + 2) - 5(3x + 2) = 0

(9x - 5)(3x + 2) = 0

9x - 5 = 0 or 3x + 2 = 0

9x = 5 or 3x = - 2

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