SOLUTION: Write an equation of a line in the form y=mx+b that passes through the points (-4, -1) and (2, -4).

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Write an equation of a line in the form y=mx+b that passes through the points (-4, -1) and (2, -4).      Log On


   



Question 636080: Write an equation of a line in the form y=mx+b that passes through the points (-4, -1) and (2, -4).
Found 2 solutions by solver91311, ewatrrr:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Use the two-point form:



where and are the coordinates of the given points.

Then rearrange it into slope-intercept form:

Note that



and a little algebra done on the two-point form after converting it to the point-slope form by substituting for , shows that:



John

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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
Line thatpasses through the points
(-4, -1) and
(2, -4) m = 3/-6 = -1/2 m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29
y = (-1/2)x + b
-4+=+%28-1%2F2%29%2A2+%2B+b+ |Using ordered pair (x,y): (2,-4) to solve for b
-2 = b
y = (-1/2)x - 2