SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to      Log On


   



Question 636066: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2.
i ended up with p=9+sqrt17, p=9-sqrt17. it says to check the answer it is supposed to ended up with one answer.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
p+-+2sqrt%28p%29+-+8+=+0
let x^2 = p
x%5E2+-+2x+-+8+=+0
(x-4)(x+2) = 0
x = 4 ⇒ p = x^2 = 16 and...16+-+8+-+8+=+0
Note: x = -2( p = 4) is an extraneous solution as 4 -4 - 8 ≠ 0