SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to      Log On

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Question 636066: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2.
i ended up with p=9+sqrt17, p=9-sqrt17. it says to check the answer it is supposed to ended up with one answer.
Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

p+-+2sqrt%28p%29+-+8+=+0

let x^2 = p

x%5E2+-+2x+-+8+=+0

(x-4)(x+2) = 0

  x = 4  ⇒   p =  x^2 = 16   and...16+-+8+-+8+=+0

Note: x = -2( p = 4) is an extraneous solution  as  4 -4 - 8 ≠ 0