SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to      Log On

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 Question 636066: p-2the square root of p then =8 the answer should be 16. i cleared the p and got rid of the -2 and ended up with 2p=64-16p+p^2. i ended up with p=9+sqrt17, p=9-sqrt17. it says to check the answer it is supposed to ended up with one answer.Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, let x^2 = p (x-4)(x+2) = 0 x = 4 ⇒ p = x^2 = 16 and... Note: x = -2( p = 4) is an extraneous solution as 4 -4 - 8 ≠ 0 ```