Question 626391: Give exact and approximate solutions to three decimal places
y^2-20y+100=16
What are the exact solutions?
y=?
(Type an exact answer as needed)
(Rationalize all denominators)
(express complex numbers in terms of I)
(use a comma to separate answers as needed)
There are no approximate solutions since the solutions are integers
Does this mean that:
1)y^2 is the ^2 of y
2)+100=10^2
3)ignoring the sign (-) on -20, the product of square roots of 1st and 3rd term = 2*y*10 (20y)
4)y = (y-10)^2=16
y-10= ±4
y = 10 ±5
Am I doing this right?
Answer by solver91311(24713)   (Show Source):
| |
|
