# SOLUTION: Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. f(x) = -2x^2 +

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. f(x) = -2x^2 +      Log On

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 Question 625526: Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. f(x) = -2x^2 + 2x + 1 The x-coordinate of the vertex is: (Type a simplified fraction) The y-coordinate of the vertex is: (Type a simplified fraction) The equation of the line of symmetry is: (Type an equation. Use integers or fractions for any numbers in the equation.) The maximum/minimum of f(x) is: (Type a simplified fraction.) The value of f(1/2) = (3/2) is a a) minimum b) maximum Any help is greatly appreciated. Thank you! Answer by lwsshak3(6513)   (Show Source): You can put this solution on YOUR website!Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. f(x) = -2x^2 + 2x + 1 complete the square f(x)= -2(x^2-x+1/4)+1+1/2 f(x)= -2(x-1/2)^2+3/2 This is an equation that opens downwards.(negative coefficient of leading term) Its standard form of equation: y=-(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex .. The x-coordinate of the vertex is: 1/2 (Type a simplified fraction) The y-coordinate of the vertex is: 3/2 (Type a simplified fraction) The equation of the line of symmetry is x=1/2 (Type an equation. Use integers or fractions for any numbers in the equation.) The maximum of f(x) is: 3/2 (Type a simplified fraction.) The value of f(1/2) = (3/2) is a b) maximum