SOLUTION: In the box, complete the first 4 steps for graphing the quadratic function given. (Use ^ on the keyboard to indicate an exponent.) Then print a sheet of graph paper and graph the q

 

Hi,

y= -x^2 - 4x - 3   Completing Square to put into Vertex Form

y = -(x+2)^2 + 4 - 3

y = -(x+2)^2 + 1  ||Parabola opens downward (-1 <0) along x = -2 , V(-2,1



See below descriptions of various conics                         

Standard Form of an Equation of a Circle is  

where Pt(h,k) is the center and r is the radius





 Standard Form of an Equation of an Ellipse is  

where Pt(h,k) is the center. (a positioned to correspond with major axis)

 a and b  are the respective vertices distances from center

 and ±are the foci distances from center: a > b



Standard Form of an Equation of an Hyperbola opening right and  left is:

   where Pt(h,k) is a center  with vertices 'a' units right and left of center 

and foci  units right and left of center along y = k



Standard Form of an Equation of an Hyperbola opening up and down is:

   where Pt(h,k) is a center  with vertices 'b' units up and down from center, 

and foci units units up and down from center, along x = h



the vertex form of a Parabola opening up(a>0) or down(a<0),  where(h,k) is the vertex.

The standard form is , where  the focus is (h,k + p)



the vertex form of a Parabola opening right(a>0) or left(a<0),  where(h,k) is the vertex.

The standard form is , where  the focus is (h +p,k )