SOLUTION: x^2-3x-6=0 (completing the square) and -6x^2=3x+2(using the quadratic formula) If you can show me how to answer these that would be great im having a little troub

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: x^2-3x-6=0 (completing the square) and -6x^2=3x+2(using the quadratic formula) If you can show me how to answer these that would be great im having a little troub      Log On


   

Question 618838: x^2-3x-6=0 (completing the square)


and -6x^2=3x+2(using the quadratic formula)




If you can show me how to answer these that would be great im having a little trouble with them.. thank you
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




Verify the lead coefficient is 1 then clear the constant to the RHS:



Divide the coefficient on the first degree term by 2, square the result, then add the result of the squaring operation to both sides.



Factor the perfect square in the LHS and do the arithmetic in the RHS:



Take the square root of both sides. Remember to consider both the postitive and negative roots.



You should be able to clean it up from here.

John

My calculator said it, I believe it, that settles it
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