SOLUTION: I have been requested to factorize the following equation for a calculus calculation I am struggling with. Y = x^3 - 3x^2 - 9x

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Question 614524: I have been requested to factorize the following equation for a calculus calculation I am struggling with.

Y = x^3 - 3x^2 - 9x - 5

I begun in the following manner.

0=x(x^2-3x-9)-5
5=x(x^2-3x-9)....

....From that point I failed to understand my calculation.

Your assistance will be highly appreciated.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Y = x^3 - 3x^2 - 9x - 5
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It looks like f(-1) = 0
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Use synthetic division to see.
-1)....1....-3....-9....-5
........1.....-4...-5...|..0

Quotient: x^2 -4x-5
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Factor the quotient:
(x-5)(x+1)
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Final factored form: (x+1)^2(x-5)
======
Note: The fastest way to find one or more
Real Number zeroes is to graph the function
with a graphing calculator. Hopefully you
have a graphing calculator, if you are studying
calculus.
Cheers,
Stan H.

SOLUTION: I have been requested to factorize the following equation for a calculus calculation I am struggling with. Y = x^3 - 3x^2 - 9x - 5 I begun in the following manner.