SOLUTION: Would someone please help me with this equation??!!!!?!?!!! Find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function and graph the function.

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Question 608399: Would someone please help me with this equation??!!!!?!?!!!
Find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function and graph the function.
f(x) = -2x^2 + 2x + 6
The question asks for:
x-coordinate
y-coordinate
The equation line of symmetry
The minimum or maximum value of the quadratic function
and whether or not the value of f(1/2) = 13/2 is a minimum or maximum
also, the graph
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
Find the vertex, the line of symmetry, the maximum or minimum value of the quatratic function and graph the function.
f(x) = -2x^2 + 2x + 6
**
This is a parabola that opens downwards:
Its standard form of equation: y=(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
y-coordinate of vertex is maximum value of function
..
f(x)= -2x^2 + 2x + 6
complete the square
f(x)=-2(x^2-x+1/4)+6+1/2
f(x)=-2(x-1/2)^2+13/2
..
Vertex: (1/2,13/2)
Line of symmetry: x=1/2
Maximum value=13/2
See graph below: