SOLUTION: HELP!!!! it says identify the axis of symmetry, create a suitable table of values, then sketch the graph.
y=-x^2+3x-3
I am so lost when it comes to these! Your help would be grea
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: HELP!!!! it says identify the axis of symmetry, create a suitable table of values, then sketch the graph.
y=-x^2+3x-3
I am so lost when it comes to these! Your help would be grea
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Question 60815: HELP!!!! it says identify the axis of symmetry, create a suitable table of values, then sketch the graph.
y=-x^2+3x-3
I am so lost when it comes to these! Your help would be greatly appreciated!
Thanks
CH Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! y = -x^2 + 3x - 3
This is a vertical parabola, so the axis of symmetry is vertical.
(-b/2a,f(x))
x = -b/2a
x = -3/-2
x = 1.5
For the table of values, think you are able to pick points and find the value from the y.
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