SOLUTION: y=x^2+x-6 It says to find the x-intercepts? I AM SO LOST! HELP! Thank you so much!! ac

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: y=x^2+x-6 It says to find the x-intercepts? I AM SO LOST! HELP! Thank you so much!! ac      Log On


   

Question 60474: y=x^2+x-6
It says to find the x-intercepts? I AM SO LOST! HELP!
Thank you so much!!
ac
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2+x-6
The x-intercepts are the points where the parabola crosses the x-axis. The values of y will always be zero.
.
y= x^2+x-6 [Factor]
y=(x-2)(x+3)
0=(x-2)(x+3) [Set each factor equal to zero and solve for x]
x-2=0
x=2
x-intercpet = (2, 0)
.
x+3=0
x=-3
The other x-intercept = (-3, 0)
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