SOLUTION: How do you solve 7y2+6=y2 and x2-1=-16

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Question 60103: How do you solve 7y2+6=y2 and x2-1=-16
Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
The given set of equations are:

7y%5E2+%2B+6 = y%5E2

Subtracting 6 + y%5E2 from both sides of the above equation, we get:

7y%5E2+-+y%5E2 = - 6


6y%5E2+ = - 6


Hence, +y%5E2+ = -1

Therefore y = + or - i rs(1)

where rs stands for radical

x%5E2+-+1 = -16

adding 1 to both sides, we get:

x%5E2 = - 15


Taking squae root, we get


x = + or - i rs(15)