SOLUTION: if 3x^2 - 4x + 7 = 0, then (x - 2/3)^2 = ???

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Question 600838: if 3x^2 - 4x + 7 = 0, then (x - 2/3)^2 = ???
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2 - 4x + 7 = 0, then (x - 2/3)^2 = ???
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Solve 3x^2-4x+7 = 0
3x^2-7x+3x+7 = 0
x(3x-7)+(3x+7) = 0
(3x-7)(x+1) = 0
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x = 7/3 or x = -1
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If x = 7/3, (x-2/3)^2 = (5/3)^2 = 25/9
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If x = -1, (x-2/3)^2 = (-5/3)^2 = 25/9
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Cheers,
Stan H.
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Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
if 3x^2 - 4x + 7 = 0, then (x - 2/3)^2 = ???
divide by 3
x%5E2-%284%2F3%29x+%2B%287%2F3%29=0
Complete the square by adding 4/9 on both sides

x%5E2-2%281%29%282%2F3%29+%2B4%2F9+%2B%287%2F3%29=4%2F9

%28x-%282%2F3%29%29%5E2%2B7%2F3+=+4%2F9
%28x-%282%2F3%29%29%5E2=+-7%2F3+%2B4%2F9

+%28x-%282%2F3%29%29%5E2=+%28-21%2B4%29%2F9

%28x-%282%2F3%29%29%5E2=%28-17%2F9%29