SOLUTION: Please help me find the standard form (function) of this quadratic equation. 3q+100=-q2/2000-4q+1000

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me find the standard form (function) of this quadratic equation. 3q+100=-q2/2000-4q+1000      Log On


   

Question 598945: Please help me find the standard form (function) of this quadratic equation.
3q+100=-q2/2000-4q+1000
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
3q+%2B+100+=+-q%5E2%2F2000+-4q+%2B+1000
0 = -q%5E2%2F2000+-+4q+-+3q+%2B+1000+-+100
0 = -q%5E2%2F2000+-+7q+%2B+900
Multiply both sides by 2000
0 = -q%5E2+-+14000q+%2B+1800000
f(q) = 0, therefore
f(q) = -q%5E2+-+14000q+%2B+1800000